jQuery可以用Ajax/serialize 把form的element都轉成query string再用Ajax
或是jQuery form plugin http://www.malsup.com/jquery/form/
Prototype 直接對form用 request就可以了
參考
$('submit').observe('click', function(){
$("info-form").request( {onSuccess: function(r) {
switch(r.responseJSON.error) {
case 0:
alert(r.responseJSON.result);
break;
}
} } );
} );
我是覺得用jQuery比較方便
Prototype需要在php令外送header才能接受json
用jQuery做AJAX post的範例 (補填個人資料)
jQuery("#send", right_block).click( function() {
jQuery.post('action_url',jQuery("#form_fill_info", right_block).serialize(),
function(data){
alert(data.msg);
if (data.error == 0)
jQuery("#fill_info", right_block).css('display', 'none');
},'json'
);
});
Friday, March 19, 2010
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